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Each player is assigned 5 numbered balls: one (let's call him Shou) gets 1 through 5; another (let's call him Chuu) gets 6 through 10; the third (call him Dai) gets 11 through 15. I am not sure if the assignment is done before the game, or during it. 207.237.35.238 The object is to be the last player with at least one ball left on the table.
I guess this is a sort of three player variant of eight ball.
Being a very good player may be to your disadvantage: if Shou is an excellent player, Chuu and Dai will cooperate against him to defeat him. I wonder what Shou's best strategy is in a case like this?